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ASP.NET AJAX PageRequestManager.getInstance サンプル

最新の投稿は、投稿日時: 2008/01/03 18:00 投稿者: ASANO です。スレッドには 2 件の返答があります。
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  • 2008/01/03 17:59

    ASP.NET AJAX PageRequestManager.getInstance サンプル

    回答 連絡

    <%@ Page Language="C#" AutoEventWireup="true"  CodeFile="Default.aspx.cs" Inherits="_Default" %>

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

    <html xmlns="http://www.w3.org/1999/xhtml">
    <head runat="server">
        <title>PageRequestManager.getInstance</title>
    </head>
    <body>

        <form id="form1" runat="server">
            <asp:ScriptManager ID="ScriptManager1" runat="server" ScriptMode="Release">
                <Scripts>
                    <asp:ScriptReference Path="~/JScript.js" />
                </Scripts>
            </asp:ScriptManager>
           
            <asp:UpdatePanel ID="UpdatePanel1" runat="server">
                <ContentTemplate>
               
                    <asp:Button ID="Button1" runat="server" Text="Button" onclick="Button1_Click" />
                    <asp:Label ID="Label1" runat="server" Text="Label"></asp:Label>
                   
                </ContentTemplate>
            </asp:UpdatePanel>
        </form>

    </body>
    </html>

  • 2008/01/03 17:59 回答元:

    Re: ASP.NET AJAX PageRequestManager.getInstance サンプル

    回答 連絡

    using System;
    using System.Web.UI;
    using System.Threading;

    public partial class _Default : System.Web.UI.Page
    {
        protected void Page_Load(object sender, EventArgs e)
        {
            ScriptManager1.AllowCustomErrorsRedirect = false;
            ScriptManager.GetCurrent(this).RegisterAsyncPostBackControl(Button1);

            ScriptManager1.AsyncPostBackError += delegate(object s, AsyncPostBackErrorEventArgs args)
            {
                Label1.Text = args.Exception.Message;
            };
        }

        protected void Button1_Click(object sender, EventArgs e)
        {
            Thread.Sleep(3000);
        }
    }
    タグ:

  • 2008/01/03 18:00 回答元:

    Re: ASP.NET AJAX PageRequestManager.getInstance サンプル

    回答 連絡

    Sys.Application.add_init(addInit);

    var control;
    function addInit(sender) {
      var instance = Sys.WebForms.PageRequestManager.getInstance();
      instance.add_beginRequest(BeginRequest);
      instance.add_endRequest(EndRequest);
    }

    function BeginRequest(sender, args) {
        control = args.get_postBackElement();
        reverseDisable(control);
    }

    function EndRequest(sender, args) {   
        reverseDisable(control);
    }

    function reverseDisable(c) {
        c.disabled = !c.disabled;
    }
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